-16x^2+101x+10=x

Solution for -16x^2+101x+10=x equation:

-16x^2+101x+10=x

We move all terms to the left:

-16x^2+101x+10-(x)=0

We add all the numbers together, and all the variables

-16x^2+100x+10=0

a = -16; b = 100; c = +10;
Δ = b2-4ac
Δ = 1002-4·(-16)·10
Δ = 10640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10640}=\sqrt{16*665}=\sqrt{16}*\sqrt{665}=4\sqrt{665}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{665}}{2*-16}=\frac{-100-4\sqrt{665}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{665}}{2*-16}=\frac{-100+4\sqrt{665}}{-32}
$